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6w^2-13w=225
We move all terms to the left:
6w^2-13w-(225)=0
a = 6; b = -13; c = -225;
Δ = b2-4ac
Δ = -132-4·6·(-225)
Δ = 5569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{5569}}{2*6}=\frac{13-\sqrt{5569}}{12} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{5569}}{2*6}=\frac{13+\sqrt{5569}}{12} $
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